Solutions to Practice Problems Week 3
Cs |
Metal |
Os |
Metal |
Ge |
Metalloid |
He |
Nonmetal |
I |
Nonmetal |
Al |
Metal |
Isotope→ |
18O |
35Cl |
78Se |
26Al3+ |
79Br- |
Protons |
8 |
17 |
34 |
13 |
35 |
Electrons |
8 |
17 |
34 |
10 |
36 |
Neutrons |
10 |
18 |
44 |
13 |
44 |
Note: There are discernible
spaces between the boxes for s, p and d orbitals. These spaces are necessary to
distinguish the identity of the electrons (the arrows). Without the spaces, the
display cannot be interpreted.
Atom |
Electronic Configuration |
# unpaired |
Orbital |
Sulfur Z = 16 |
|
2 |
3p |
Zinc Z = 30 |
|
0 |
3d |
Niobium Z = 41 |
|
3 |
4d |
Tellurium Z = 52 |
|
2 |
5p |
Given |
Correct |
F: 1s22s22p5 |
OK |
Mn: [Ar]4s24d5 |
Mn: [Ar]4s23d5 |
Rb: [Kr]5s1 |
OK |
N: 1s22s22p |
N: 1s22s22p3 |